Program untuk menghitung perkalian deret bilangan ganjil membentuk segitiga siku di Java

Soal :

1 = 1

1 * 3 = 3

1 * 3 * 5 = 15

1 * 3 * 5 * 7 = 105

1 * 3 * 5 * 7 * 9 = 945



Coding:

package allaboutalgoritma;
import java.util.Scanner;
/**
*
* @author dimata005
*/
public class Main {

/**
* @param args the command line arguments
*/
public static void main(String[] args) {

int i, j, min, jum;

boolean prima;
Scanner input = new Scanner(System.in);

System.out.print("Masukkan nilai batas awal: ");
min = input.nextInt();

for (i=1;i<=min;i++)
{
if (i%2!=0){
jum=1;
for (j=1;j<=i;j++)
{
if (j != 1 && j%2!=0){
System.out.print("*");
}
if(j%2!=0){
System.out.print(j);//<<j;
jum = jum * j;
}else if (j==1){
System.out.print(j);//<<j;
jum = jum * j;
}
}
System.out.println("\t\t= "+jum);//"\t\t= "<<jum<<endl;
}
}
}

}

untuk contoh lain menggunakan bahasa C bisa di coba di sini http://diary-mybustanoel.blogspot.com/2011/12/program-untuk-menghitung-perkalian.html